Light-NCERT Solutions

Q.1.   Suppose you are in a dark room. Can you see objects in the room? Can you see objects outside the room? Explain.

Ans. We see only those objects from which reflected rays enter our eyes. When we are in a dark room then we do not see objects, We can see objects outside the room because out of the room the light is available and those rays of light enter our eyes after reflection.

Q.2.   Differentiate between regular and diffused reflection. Does diffused reflection mean the failure of the law of reflection?

Ans. Difference between regular and diffused reflection:

              Regular Reflection

             1. It takes place on a smooth and shiny surface.

1. It. takes place on a rough surface.

             2. In this case all rays are parallel after reflection.

2. Reflected rays are in different direction.

Diffused reflection is not due to the failure of the laws of reflection. It is caused by the irregularities in the reflecting surface.

Q.3.   Mention against each of the following whether regular or diffused reflection will take place when a beam of light strikes. Justify your answer in each ease.

             (a) Polished wooden table

(b) Chalk powder

             (e) Card board sufrace

(d) Marble floor with water spread over it.

             (e) Mirror (f) Piece of paper.

Ans. (a) A regular reflection takes place on a polished wooden table because its surface is smooth.

             (b) A diffused reflection takes place on a chalk powder because its surface is uneven.

             (c) Card board surface has minute irregularities on it, so it will have a irregular reflection.

             (d) Marble floor with water spread over acts as a surface for a regular reflection as it will act like a plane surface.

             (e) Mirror has a regular reflection, Its surface is also shiny and has smooth surface,

             (f) At a piece of a paper takes irregular or diffused reflection because it has uneven surface.

Q.4.   State the laws of reflection,

Ans. There are two laws of reflection.

             (i) Angle of incidence is always equal to the angle of reflection.

                  i.e. ∠i = ∠r

             (ii) The incident ray, the normal at the point of incidence and the reflected ray all lie in the same plane.

Q.5.   Describe an activity to show that the incident ray, the reflected ray and the normal at the point of incidence lie in the same plane.

Ans. For this experiment take a plane mirror and stand it on a plane sheet of paper with a block. Now draw an incidence line AB. Now see in the mirror and mark the points on the paper, where you fill the line is travelling after getting reflected from the mirror. Remove the mirror and draw a perpendicular on the mirror line. Join the points to make the reflected ray. You will see that incident ray, reflected ray and normal will be in the same plane, i.e. on the sheet of paper.

Fig. 16.8 Drawing the normal.

Q.6.   Fill in the blanks in the following:

             (a) A person 1 m in front of a plane mirror seems to be _______m away from his image.

             (b) If you touch your _______ ear with right hand in front of a plane mirror it will be seen in the mirror that your right ear is touched with_______.

             (c) The size of the pupil becomes_______ when you see in dim light.

             (d) Night birds have_______cones than rods in their eyes.

Ans. (a) 2          (b) left, left hand          (c) large          (d) lesser

Q.7.   Angle of incidence is equal to the angle of reflection.

             (a) Always

(b) Sometimes

             (c) Under special condition

(d) Never.

Ans. (a) Always

Q.8.   Image formed by a plane mirror is:

             (a) virtual, belu,nd the mirror and enlarged.

             (b) virtual, behind the mirror and of the same size as the object.

             (c) real at the surface of the mirror and enlarged.

             (d) real, behind the mirror and of the same size as the abject.

Ans. (b) Virtual, behind the mirror and of the same size as the object.

Q.9.   Describe the construction of a kaleidoscope.

Ans. Kaleidoscope is made up of three rectangular mirror strips each about 15 cm long and 4 cm wide. Join them together to form a prism. Fix them in circular cardboard tube. Make sure that the tube is slightly longer than the mirror strips. Close one end of the tube by a cardboard disc having a hole in the centre. To make the disc durable, paste a piece of transparent plastic sheet under the cardboard disc. At the other end, touching the mirrors, fix a circular plane glass plate.

Fig. 16.9. Making a kaleidoscope.

Q.10.   Draw a labelled sketch of the human eye.

Q.11.   Gurmit wanted to perform activity 16.8 using a laser torch. Her teacher advised her not to do so. Can you explain the basis of the teacher's advise?

Ans. Laser light is harmful for eye and can cause a permanent defect in the eye. She can lose her eyesight also.

Q.12.   Explain how you can take care of your eyes.

Ans. Following cares are required for our eyes:

             (i) Do not read in too little or too much light.

             (ii) Wash your eyes with cold water at least three times.

             (iii) Do not look at the sun or powerful light directly.

             (iv) Always read at the normal distance for vision.

             (v) Do not rub your eyes with dirty hand.

Q.13.   What is the angle of incidence of a ray if the reflected ray is at an angle of 90� to the incident ray?

Ans. The angle of incidence ray will be 45°.

Q.14.   How many images of a candle will be formed if it is placed between two parallel mirrors separated by 40 cm?

Ans. Infinite number of images will be formed.

Q.15.   Two mirrors meet at right angles. A ray of light rs incident at an angle of 30° as shown in Fig. 16.10. Draw the reflected ray from the second mirror.

Fig. 16.10

Q.16.   Boojho stands atA just on the side of a plane mirror as shown in Fig. 16.11. Can he see himself in the mirror? Also can. he see the image of objects situated at P, Q and R?

Fig. 16.11

Ans. He cannot see his image himself. He can see only the image of P but not Q and R

Q.17.   (a) Find out the position of the image of an object situated at A in the plane mirror (Fig, 16.12).

             (b) Can Paheli at B see the image?

             (c) Can Boojho at C see this image?

             (d) When Paheli moves from B to C, where dries the image of A move?

Fig. 16.12

Ans. (a)

             (b) Yes, Paheli can see the image at B.

             (c) Yes, Boojho can see the image.

             (d) No change of image A.